Question

2/3j=1/4+2/3-j/3 for j=5/6

​

Answer 1

what i find??

i don't getting understand

Answer 2

Suppose that a = 2b + 1 and k = 2b2 - 1. Then we get the equation

1 = (m - an)2 - (4b2 - 2)n2,

which is satisfied by (m, n) = (2b + 1, 2b) and (8b2 + 2b - 1, 2b). The first of

these yields the two triples

(8b3 + 2b2 - 4b - 1, 16b4 + 8b3 - 8b2 - 4b, 16b4 + 8b3 - 6b2 - 4b - 1),

(8b3 + 2b2 - 2b, 16b4 + 8b3 - 8b2 - 2b + 1, 16b4 + 8b3 - 6b2 - 2b + 1).