Math, asked by atulkumarmishrakumar, 8 months ago

(2^3n-1) is a multiple of 7.​

Answers

Answered by Krishnashandilya
2

Answer:

2^(3n) - 1

= 2^(3n) - 1^n

= 8^n - 1^n

= (8-1)(8^(n-1) + .....+ 1)

= 7 x Some Integer

This is divisible by 7

Answered by Anonymous
5
(2^3n -1) is a multiple of 7


True


Hope it helps you
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