Question

2/3of a no. is less than the original no. by 10 .find the original no.
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Answer 1

Answer:

Let the original number be x.

2/3 of the number=⅔x

The number=⅔x+10

Now, since we know the above facts, we can solve the question very easily.

According to the problem:

⅔x+10=x

=>x-10=⅔x

(transposing 10)

=>x-⅔x=10

(transposing ⅔x and 10)

=>3x/3 - 2x/3 = 10

(Multiplying x's numerator and denominatiors by 3)

=>x/3=10

(Subtracting 2x from 3x)

=>x=10×3=30

Answer- The original number is 30

Answer 2

Answer:

30

Step-by-step explanation:

Define x:

Let the original number be x.

2/3 of the number is 10 less than the number:

$\dfrac{2}{3} x = x - 10$

Solve x:

$\dfrac{2}{3} x = x - 10$

$\dfrac{2}{3} x - x = - 10$

$-\dfrac{1}{3}x = -10$

$\dfrac{1}{3} x = 10$

$x = 30$

Answer: The original number is 30