Question

(2/3p-3/4q)^2 using algebraic identities​

Answer 1

Answer:

Given:-

($\frac{2}{3}$p-$\frac{3}{4}$p)²

This Can be solved by the Identity (a-b)²

So,

We know that:-

(a-b)²=a²-2ab+b²

Therefore:-

($\frac{2}{3}$p-$\frac{3}{4}$p)²

($\frac{2}{3}$p)²- 2×$\frac{2}{3}$p×$\frac{3}{4}$p +($\frac{3}{4}$p)²

$\frac{4}{9}$ p² -p²+$\frac{9}{16}$p²

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Answer 2

Step-by-step explanation:

(2/3p-3/4q)^2

Using identity : - (a-b)^2

=> a^2 +b^2 -2ab

putting these values:- (2/3p)^2 + (-3/4q)^2 - 2*2/3p*(-3/4q)

=> 4/9p^2-9/16q^2-1pq