Question

2/3rd of the balls in a bag are blue, the rest are pink.
if 5/9th of the blue balls and 7/8th of the pink balls are
defective, find the total number of balls in the bag given
that the number of non defective balls is 146.

Answer 1

Let the total numbers of the ball in a bag be x.

Blue balls = 2/3 of x

Pink ball = x - 2x/3

= x/3

Now,

Defective Blue balls = 5/9 of (2/3 of x)

= 5/9 × 2/3 × x

= 10/27 × x

Defective Pink balls = 7/8 of x/3

= 7x/24

Now, According to the Question, Defective Blue and Pink balls = 146

10x/27 + 7x/24 = 146

⇒ (80x + 63x)/216 = 146

∴ 143x = 146 × 216

⇒ x = 220.53

≈ 221 balls.

Hence, the total numbers of the ball in a a bag is 221 balls.

Hope it helps.

Answer 2

Solution :-

Let the total Number of balls = X

Blue balls = 2x / 3

Pink balls = x- 2x / 3

= x / 3

Than,

defactiv blue balls 5/9 of ( 2/3of x)

= 5/9 × 2/3 × x

= 10/27 x

Defective pink balls = 7 / 8 × x/3
= 7x / 24

Total no of defective balls = 10x/27 +7x/24
=143x/216

non defective balls= 143x/216=146

x= 216×146/ 143

x= 31,536 / 143

x = 220.53 ~ 221

Hence the total number of balls in the bag is 221 balls

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I hope it's help you....!!!