2+3sinx+4cosx find the maximum value?
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Answer:
in general
maximum value of
asinx + bcosx = √(a²+b²)
the maximum value of 3sinx+4cosx
is √(9+16) = √25 = 5
the maximum value of 2+3sinx+4cosx
= 2 + 5 = 7
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