Question

2
3v.
(d)
towards right
2.
69. A sphere of mass m is held between two smooth
3
inclined walls. For sin 37° = the normal reaction of
5
the wall (2) is equal to
(2)
(1)
379
370
(a)
(b)
25 mg
39
16 mg
25
39 mg
21
(d) None of these​

Answer 1

Answer:

okkkk

Explanation:

amizing question

Answer 2

Answer:

Explanation:

Mg=2Rsin370

R=2sin370Mg​

R=2×53​Mg​(sin370=53​)------------given

therefore, R=65Mg​

this sphere is lying between 2 inclined planes so there are 2 normal reactions on the sphere by the plane.

if we resolve these reactions the vertical forces will be Rsin370×2 this system is under equilibrium.

So, vertical forces Rsin370 is equal to weight of he sphere Mg ( here assume normal reaction =R)