Math, asked by lahari1047, 3 months ago

2^3x-1+10/7=6 find the value of x​

Answers

Answered by skephalo
0

Answer:

Exact form:

x=39/56

Decimal form:

x= 0.69642857

Answered by adprasad
0

Answer:

x= 1/3 (log 39/7 to the base 2)

Step-by-step explanation:

2^3x - 1 + 10/7 = 6

[(7 × 2^3x) - (1 ×7) + 10]/7 = 6

7 × 2^3x + 3 = 42

7 × 2^3x = 39

2^3x = 39/7

3x = log 39/7 to the base 2. { if a^x = N then, x = log N to the base a }

x= 1/3 (log 39/7 to the base 2)

Similar questions