2^3x-1+10/7=6 find the value of x
Answers
Answered by
0
Answer:
Exact form:
x=39/56
Decimal form:
x= 0.69642857
Answered by
0
Answer:
x= 1/3 (log 39/7 to the base 2)
Step-by-step explanation:
2^3x - 1 + 10/7 = 6
[(7 × 2^3x) - (1 ×7) + 10]/7 = 6
7 × 2^3x + 3 = 42
7 × 2^3x = 39
2^3x = 39/7
3x = log 39/7 to the base 2. { if a^x = N then, x = log N to the base a }
x= 1/3 (log 39/7 to the base 2)
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