Question

(2^3x-1+10)÷7=6 plss tell urgently ​

Answer 1

2^(3x-1)+10=7×6=42

=> 2^(3x-1) = 32

=> 2^(3x-1) = 2^5

As LHS IS HAVING SAME BASE AS THAT OF RHS therefore, we can now easily compare the powers

Therefore, => 3x-1 = 5

=> 3x = 6

=> X = 2

Answer 2

soln:-

(2^(3x-1)+10)÷7=6

=) 2^(3x-1)+10=42

=) 2^3x-1=32

=) 2^3x-1=2⁵

｡*｡On comparing the power,

3x-1=5

=) 3x=6

=) X=2.