Question

2^3x+1 + 2^7=2^8 then 2^x=?​

Answer 1

Answer:

Let the three consecutive integers be x, x + 1 and x + 2.

According to the question,

2x + 3(x + 1) + 4(x + 2) = 74

=> 2x + 3x + 3 + 4x + 8 = 74

=> 9x + 11 = 74

=> 9x = 74 – 11

=> 9x = 63

=> x = 63/9

=> x = 7

Hence first integer = 7, second integer = 7 + 1 = 8 and third integer = 7 + 2 = 9.