Question

2^(3x+1)= 4^3, find x​

Answer 1

Answer:

$2 {}^{2} (3x + 1) = 4 {}^{3}$

$= 6x {}^{2} + 4 = 64$

$= 6x {}^{2} - 64 - 4$

$= 6x {}^{2} - 68$

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