Question

2√3x^2-2√2x-√3=0 solve for x​

Answer 1

2√3x² -2√2x - √3

D = b² - 4ac

D = (-2√2)² - 4(2√3)(-√3)

D = 8 + 24

D = 32

x = - b + √D / 2a or - b - √D / 2a

x = + 2√2 + √32 / 4√3 or

+2√2 + √32 / 4 √3

= + 2√2 + 4√2 / 4√3 or 2√2 - 4√2 / 4√3

= 6√2 / 4 √3 or - 2√2 / 4√3

= 3√2 / 2√3 or - √2 / 2√3

= √3 × √3 × √2 / √2 ×√2 × √3. or

- √2 / √2 × √2 × √3

= √3 / √2 or - 1 / √6.

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