Question

2√3x^2+x-5√3 pls solve n give​

Answer 1

The factors of $2\sqrt{3}x^{2}+x-5\sqrt{3}$ are $(x+\sqrt{3})(2\sqrt{3}x-5)$.

Step-by-step explanation:

The expression is:

$2\sqrt{3}x^{2}+x-5\sqrt{3}$

Factorize the expression by splitting the middle term as follows:

$2\sqrt{3}x^{2}+x-5\sqrt{3}=2\sqrt{3}x^{2}+6x-5x-5\sqrt{3}$

                            $=2\sqrt{3}x(x+\sqrt{3})-5(x-\sqrt{3})\\=(x+\sqrt{3})(2\sqrt{3}x-5)$

Thus, the factors of $2\sqrt{3}x^{2}+x-5\sqrt{3}$ are $(x+\sqrt{3})(2\sqrt{3}x-5)$.

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