Question

(2\3x+2y)+(3/3x-2y=17/5
(5/3x+2y)+(1/3x-2y)=2
Find the value of x and y by elimination method.

Answer 1

Answer:

Step-by-step explanation:

let's assume 1/3x+2y= n and 1/3x-2y = s

 

now question simple :

equation becomes

 

2n+3s=17/5 ⇒ 10n+15s = 17 (1)

and 5n+s= 2 (2)

solving equations using substitution

s=2-5s in (1) we get

s=1and n=1/5

⇒3x+2y=5 (3) and 3x-2y=1  (4)

later on again solving equations using substitution 2y = 5-3x in (4) we get

x=1 and y = 1

hope this helps