Question

2^3x+3 = 2^3x+1 + 48
solve for x
(Hint : Ans. 1)​

Answer 1

Answer:

As given⇒2 ^3x+3=2 ^3x+1+48

⇒2 ^3x+3−2 ^3x+1=48

⇒2^ 3x(2 ^3−2 ^1)=48

⇒2 ^3x (8−2)=48

⇒2 ^3x (6)=48

⇒2 ^3x= 48/6

⇒2 ^3x =8

⇒2 ^3x =2 ^3

Base are same so equating powers,

3x=3

∴x=1

Answer 2

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