(2/3x + 3/2y)sq with suitable identities
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Answer:
(3x+2y)
2
+(3x−2y)
2
Using identity:
(a+b)
2
=a
2
+b
2
+2ab
(a−b)
2
=a
2
+b
2
−2ab
Therefore,
(3x+2y)
2
+(3x−2y)
2
=[(3x)
2
+(2y)
2
+2(3x)(2y)]+[(3x)
2
+(2y)
2
−2(3x)(2y)]
=[9x
2
+4y
2
+12xy]+[9x
2
+4y
2
−12xy]
=9x
2
+4y
2
+12xy+9x
2
+4y
2
−12xy
=18x
2
+8y
2
=2(9x
2
+4y
2
)
Hence (3x+2y)
2
+(3x−2y)
2
=2(9x
2
+4y
2
).
Step-by-step explanation:
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