(2/3x+4)(3/2x+6)-(1/7x-1)(1/7x+1)
Answers
Answer:
what divyanshu
Step-by-step explanation:
stop spamming others. I told you that day, didn't I? I am really sorry but this guy just copies the answers from the other guy who is writing the answer and performs like it's his owns. and if there is no one answering other than him then he just writes anything irrelevant to the answer.
sorry
Answer:
\dfrac{(8x + 35) (6x + 35)}{49}
49
(8x+35)(6x+35)
Step-by-step explanation:
(\dfrac{2}{3}x + 4)( \dfrac{3}{2}x + 6) - (\dfrac{1}{7}x - 1)(\dfrac{1}{7}x + 1)(
3
2
x+4)(
2
3
x+6)−(
7
1
x−1)(
7
1
x+1)
Expand:
= (\dfrac{2}{3}x)(\dfrac{3}{2}x) + (\dfrac{2}{3}x)(6) + 4(\dfrac{3}{2}x) + 4(6) - [ (\dfrac{1}{7}x)^2 - (1)^2]=(
3
2
x)(
2
3
x)+(
3
2
x)(6)+4(
2
3
x)+4(6)−[(
7
1
x)
2
−(1)
2
]
Evaluate each term:
= x^2 + 4x + 6x + 24 - \dfrac{1}{49}x^2 +1=x
2
+4x+6x+24−
49
1
x
2
+1
Combine like terms:
= \dfrac{48}{49}x^2 + 10x + 25=
49
48
x
2
+10x+25
Put into single fraction:
= \dfrac{48x^2 + 490x + 1225}{49}=
49
48x
2
+490x+1225
Factorise:
= \dfrac{(8x + 35) (6x + 35)}{49}=
49
(8x+35)(6x+35)