Question

(2/3x+ 4) (3/2x+ 6) - (1/7x-1) (1/7x+1​

Answer 1

$(\frac{2}{3x + 4} )( \frac{3}{2x + 6} ) - ( \frac{1}{7x - 1} )( \frac{1}{7x + 1} ) \\ \\ \frac{6}{6 {x}^{2} + 26x + 24} - \frac{1}{49 {x}^{2} - 1 } \\ \\ \frac{294 {x}^{2} - 6 - (6 {x}^{2} + 26x + 24)}{({6 {x}^{2} + 26x + 24})(49 {x}^{2} - 1) } \\ \\ \frac{288 {x}^{2} - 26x - 30}{{({6 {x}^{2} + 26x + 24})(49 {x}^{2} - 1) } }$