Question

2(3x - 4)(x + 2) = Ax2 + Bx + C. What are the values of A, B and C?

Answer 1

Answer:

3(2x-4)(x+2)=ax²+bx+c

or,3(2x²+4x-4x-8)=ax²+bx+c

or,6x²-24=ax²+bx+c

or,(6)x²+(0)x+(-24)=ax²+bx+c

so now we can write the values of coefficients a, b ,c

so, a=6

b=0

c=(-24)

hope it will help you...