(2) 3x + 4y = 10 and 2x - 2y = 2 by elimination
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3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
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3x+4y=10
3x−3y=3
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7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x= 6/3 =2
Hence x=2,y=1.
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