Question

2(3x-5)/3 = -4(x-2)/7​ find the value x​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto \dfrac{2(3x - 5)}{3} = \dfrac{ - 4(x - 2)}{7}$

$\sf \longmapsto \dfrac{6x - 10}{3} = \dfrac{ - 4x + 8}{7}$

Now,cross multiply to both sides:

$\sf \longmapsto7(6x - 10) = 3( - 4x + 8)$

$\sf \longmapsto42x - 70 = - 12x + 24$

$\sf \longmapsto42x + 12x = 24 + 70$

$\sf \longmapsto54x = 94$

$\sf \longmapsto \: x = \dfrac{94}{54} = \dfrac{47}{27}$

$\sf \bold{x = \dfrac{47}{27} }$

Check:-

LHS

$\sf \longmapsto \dfrac{2(3x - 5)}{3} = \dfrac{2({ \cancel{3}} \times \frac{47}{{ \cancel{27}}} - 5) }{3} = \dfrac{2( \frac{47}{9} - 5)}{3}$

$\sf \longmapsto \dfrac{2( \frac{47 - 45}{9} )}{3} = \dfrac{2( \frac{2}{9} )}{3} = \dfrac{ \frac{4}{9} }{3} ={ \red{ \dfrac{4}{27} }}$

RHS

$\sf \longmapsto \dfrac{ - 4(x - 2)}{7} = \dfrac{ - 4( \frac{47}{27} - 2) }{7} = \dfrac{ - 4( \frac{47 - 54}{27} )}{7}$

$\sf \longmapsto \dfrac{ \frac{ \cancel{{28}}}{27} }{{ \cancel{7}}} = { \red{ \dfrac{4}{27} }}$

∴LHS=RHS(verified)