Question

2 ( 3x + 5) - 3 + 4x < 7

Answer 1

Answer:

2/3x-5=3/4x+7.

We move all terms to the left:

2/3x-5-(3/4x+7.)=0

Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R

Domain of the equation: 4x+7.)!=0

x∈R

We add all the numbers together, and all the variables

2/3x-(3/4x+7)-5=0

We get rid of parentheses

2/3x-3/4x-7-5=0

We calculate fractions

8x/12x^2+(-9x)/12x^2-7-5=0

We add all the numbers together, and all the variables

8x/12x^2+(-9x)/12x^2-12=0

We multiply all the terms by the denominator

8x+(-9x)-12*12x^2=0

Wy multiply elements

-144x^2+8x+(-9x)=0

We get rid of parentheses

-144x^2+8x-9x=0

We add all the numbers together, and all the variables

-144x^2-1x=0

a = -144; b = -1; c = 0;

Δ = b2-4ac

Δ = -12-4·(-144)·0

Δ = 1

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=1√=1

x1=−b−Δ√2a=−(−1)−12∗−144=0−288=0

x2=−b+Δ√2a=−(−1)+12∗−144=2−288=−1/144

I hope these help u