Question

2/3x+5<=1/2x+6. where x belongs to W​

Answer 1

Answer:

the answer is .......

Step-by-step explanation:

CASE 1 :—

CASE 1 :—WHEN ⅔x + 5 = ½x + 6

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW,

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM )

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get,

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get,

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1 from this case,

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1 from this case,x < 6

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1 from this case,x < 6 hence the range of x is (–∞ , 6 )

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1 from this case,x < 6 hence the range of x is (–∞ , 6 )hope this helps !

CASE 1 :—WHEN ⅔x + 5 = ½x + 6 NOW, => ⅔x - ½x = 6 - 5 ( by transferring like terms )=> 4/6x - 3/6x = 1 ( by taking LCM ) => 1/6x = 1 => x = 6 ( by transferring 6 to RHS )NOW, CASE 2 WHEN, ⅔x - ½x < ½x + 6 by simplifying,we get, 1/6x < 1 from this case,x < 6 hence the range of x is (–∞ , 6 )hope this helps ! please like