Question

2/3x +5y=12, x+3/2y=6​

Answer 1

x=3 , y=2

Step-by-step explanation:

subtract both equations and then find value of 'y' then put 'y' in equation (1)

Answer 2

Answer:

The solution set of the equation is (2, 3).

Step-by-step explanation:

Given the equations, $\frac{2}{3} x +5y=12$        ....(1)

And $x+\frac{3}{2} y=6$                                       ....(2)

To remove 3 from the denominator, multiplying each term with 3 in equation (1),

$\frac{2}{3} x +5y=12\implies 2 x +15y-36=0$            ....(3)

To remove 2 from the denominator, multiplying each term with 2 in equation (2),

$x+\frac{3}{2} y=6\implies 2x+3 y-12=0$                  ....(4)

Subtracting equation (4) from equation (3),

$(2 x +15y-36)-(2x+3 y-12)=0$

$\implies 2 x +15y-36-2x-3 y+12=0$

$\implies 12y-24=0$

$\implies y=\frac{24}{12} =2$

Substituting the value of y in equation (4),

$2 x +15y-36=0\implies 2 x +15\times 2-36=0$

$\implies 2 x +30-36=0$

$\implies 2 x-6=0$

$\implies 2 x=6\implies x=\frac{6}{2} =3$

Therefore, the value of x = 3 and y = 2.

the solution set of the equation is (2, 3).