Question

2/3x + 9=3/4 -7 plz answer no spam​

Answer 1

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$\longrightarrow \sf \frac{2}{3x} + 9 = \frac{3}{4} -7 \\ \\ \longrightarrow \sf\frac{2+27x}{3x} = \frac{3 -28}{4} \\ \\\longrightarrow \sf 3x(3 - 28) = 4(2 +27x) \\ \\\longrightarrow \sf 9x - 84x = 8 + 108x \\\\\longrightarrow \sf 9x - 84x-108x = 8 \\ \\ \longrightarrow \sf-183x = 8\\ \\\longrightarrow \boxed { \sf x = - \frac{8}{183}}$

Answer 2

Question :

$\dfrac{2}{3x} + 9 = \dfrac{3}{4} - 7$

• Find the value of x

Solution :

$\dfrac{2}{3x} + 9 = \dfrac{3}{4} - 7$

$\implies \: \dfrac{(2 + 27x)}{3x} = \dfrac{(3 - 28)}{4}$

$\implies \: 4(2 + 27x) = 3x(3 - 28)$

$\implies \: 8 + 108x = 9x \: - \: 84x$

$\implies \: 8 = -75x-108x$

$\implies \: x = \dfrac{-183}{8}$

• Therefore, the value of x is -183/8