Question

2√3x²-5x+√3
pls tell me the answer.. ​

Answer 1

Answer:

I presume that this is supposed to be a quadratic expression, thus the first term should be 2√3x^2.

Let’s use this quadratic expression in an equation:

2√3x²-5x +√3= 0

Now, if we have a quadratic equation in the form:

ax²+bx+c=0

we have a simple formula to determine the roots of the quadratic:

x=−b±√b2−4ac/2a

Substituting a=2√3, b=−5 and c=√3

x=5±√25−24/4√3√=5±14√3

⇒x=√3/2or x=1/√3

Using these roots, we can rewrite the equation as:

D(x−3√2)(x−13√)=0

If we were to multiply out the parentheses, it should be clear that the coefficient of the x2 term would be D , whereas in our original quadratic we have the coefficient as 23–√ , this means that D=23–√ .

So the quadratic equation becomes:

2√3(x−√3/2)(x−1/√3)=0

Let’s rearrange this by moving the 2√3 inside the parentheses by multiplying the terms within the first pair of parentheses by 2 and the terms within the second pair by √3 , giving:

(2x−√3)(√3x−1)=0

As we started by adding ‘= 0’ to a quadratic expression to make a quadratic equation, less reverse this process, which gives us:

(2x−√3)(√3x−1)

Voila! We have factorised the original expression