Math, asked by vipashaverma12345, 10 months ago

х^2 – 3xy — 40у^2 plz tell

Answers

Answered by ANGEL123401
12

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 =  {x}^{2}  - 3xy - 40 {y}^{2}  \\  =  {x}^{2}  - (8 - 5)xy - 40 {y}^{2}  \\   = {x}^{2}  - 8xy + 5xy - 40 {y}^{2}  \\  = x(x - 8y) + 5y(x - 8y) \\ =  (x - 8y)(x + 5y) \\  -  >  \:  \: x = 8y \:  \\ -   >  \:  \:  x =  - 5y

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