Question

(-2+3y+20z)bracket minus 2 X + 3 Y + 2 Z Square ​

Answer 1

Answer:

${4x}^{2} + {9y}^{2} + {4z}^{2} - 12xy + 12yz - 8zx$

Step-by-step explanation:

${(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + 2zx \\ {( - 2x + 3y + 2z)}^{2} = ( { - 2x}^{2} ) + ( {3y}^{2} ) + ( {2z)}^{2} + 2 \times - 2x \times 3y + 2 \times 3y \times 2z + 2 \times 2z \times - 2x \\ = {4x}^{2} + {9y}^{2} + {4z}^{2} - 12xy + 12yz - 8zx$