Question

2х - 3y/4 = 3 & 5x-2y-7=0​

Answer 1

Step-by-step explanation:

2x-3y/4 =3

= 2x-3y/4

= 6xy =3

= 6xy× 3

= 18xy ..

2.. 3 & 5x-2y-7=0

= 3×5x-2y-7=0

= 15x - 5y =0

= 10 xy =0

10xy×0

= 0xy

The answer is 1. Ka 18xy ..

2. Ka 0xy ...

I HOPE IT WILL BE RIGHT ANSWER....

Answer 2

Answer:

x = 3 and y = 4

Step-by-step explanation:

2x - 3y/4 = 3 and 5x - 2y - 7 = 0

2x - 3y/4 = 3 and 5x - 2y = 7

8x - 3y = 12 and 5x - 2y = 7      ( In first equation multiply 2x and 3 by 4 )

Now,

x = 12 + 3y /8                     eqn.1        ( Shift all the terms to RHS )

Substitute value of x in 5x - 2y = 7

{ 5 × [ 12 + 3y / 8 ] } - 2y = 7

( 60 + 15y / 8 ) - 2y = 7

60 + 15y - 16y = 56                     ( Multiply -2y and 7 by 8 )

60 - 56 + 15y - 16y = 0                ( Shifting 56 to LHS )

4 - y = 0

y = 4                                    eqn. 2

Now, substitute value of y in eqn. 1

x = 12 + ( 3 × 4 )/8

x = 12 + 12/ 8

x = 24/8

x = 3

Hence values of x = 3 and y = 4