Question

(2⁰+4-1)×2² is equal to
(2,3,4,5)

Answer 1

Step-by-step explanation:

Given that:-

(2^0+4^-1)×2^2

we know that a^0=1

=>(1+4^-1)×4

we know that a^-n=1/(a^n)

=>(1+1/4)×4

=>[(4+1)/4]×4

=>(5/4)×4

=>(5×4)/4

=>5

Answer:-

(2^0+4^-1)×2^2=5

Used formulae:-

• a^0=1
• a^-n=1/(a^n)