Question

(2х - у) - 4(2x - у)^2 factorise​

Answer 1

Step-by-step explanation:

$(2x-y)-4(2x-y) ^ { 2 }$

solution

$2x-y-4\left(4x^{2}-4xy+y^{2}\right)$

$2x-y-16x^{2}+16xy-4y^{2}$

$-16x^{2}+16xy+2x-4y^{2}-y$

Answer 2

Answer:

Answer

(x+2y)

2

−4(2x−y)

2

=(x+2y)

2

−(2(2x−y))

2

=(x+2y)

2

−(4x−2y)

2

is of the form a

2

−b

2

=(a−b)(a+b)

=(x+2y−4x+2y)(x+2y+4x−2y)

=(−3x+4y)(5x)

=5x(4y−3x)