Question

2+4/3+8/9+....9th terms and nth terms​

Answer 1

Explanation:

= 2 + 4/3 + 8/9 + 16/27 + 32/81 + .... + 512/19,683

= Series is in GP.

=> a = 2 , n = 9 , r=2/3

Sum of first 9 terms.

=> S9 = a(1 - r^n)/(1-r)

=> S9 = 2*(1 - (2/3)^9)/(1-2/3)

=> S9 = 2*(3^9 - 2^9)/3^9*(1/3)

=> S9 = 2*19171/6561

=> S9 = 5.8439

sum of first n terms

=> Sn = a/(1-r)

=> Sn = (2)/(1-2/3)

=> Sn = 2*3/(3-2)

=> Sn = 6