Question

2
4
3. Find the minors of -1 and 3 in the matrix (2 -1 4
0-2 5
: -31 3)​

Answer 1

Answer:  det (A - lambda * I) = 0

where:

A= a square matrix, ex: [2 5 4;8 6 9;3 4 6]

I= identity matrix

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Step-by-step explanation:  

There are, in general, multiple solutions (values of lambda) which satisfy the equation det(A-lambda*I)=0. eig(A) returns a vector, each element of which is one solution.

For an n-by-n matrix A, the vector returned by eig(A) will have length n. That is because det(A-lambda*I) is a degree-n polynomial, and hence has n (possibly complex) roots by the fundamental theorem of algebra. Note that some values may be repeated; that indicates the algebraic multiplicity of the root.