Question

2+ 4 + 6+ ..... + 20 ) - (1+ 2 + 3 + ..... +10) ​

Answer 1

Answer:

Using\quad (a−b)

3

=a

3

−b

3

−3ab(a−b)

Take\quad a=x,b=

3

2

y

(x−

3

2

y)

3

=x

3

−(

3

2

y)

3

−(3x)(

3

2

y)(x−

3

2

y)

=x

3

−

27

8

y

3

−2xy(x−

3

2

y)

=x

3

−

27

8

y

3

−2xy(x)−2xy(−

3

2

y)

=x

3

−

27

8

y

3

−x

2

y+

3

4

xy

2

Answer 2

Step-by-step explanation:

2+4+6+...+20 = 32 and 1+2+3+...+10 =16 and it will be sud =46