2+4+6+8+10+12...........500=
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Answered by
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Here, we need to find sum of all Even Numbers upto 500.
The best and easiest method is to form an A.P.
First Term(A) = 2
Last Term(L) = 500
Common Difference(D) = 2(Even Numbers)
No. of terms(N) = 250(Since, there are always equal no. of even and odd numbers)
Now, S(N)= N/2(A+L)
=S(250)= 250/2(2+500)
=250×251
=62,750 ANSWER
Please hit the Thank You button if you understood the answer well !!
The best and easiest method is to form an A.P.
First Term(A) = 2
Last Term(L) = 500
Common Difference(D) = 2(Even Numbers)
No. of terms(N) = 250(Since, there are always equal no. of even and odd numbers)
Now, S(N)= N/2(A+L)
=S(250)= 250/2(2+500)
=250×251
=62,750 ANSWER
Please hit the Thank You button if you understood the answer well !!
CHPhani:
good try
Thanks! Hit the Brainliest button if you consider the answer worthy enough and if not, please tell me where are you finding it difficult to understand. I would simplify it furrther
Answered by
0
Sn= (n/2)*( a +l ) Tn= a + (n-1)d
= (250/2) * (2+500) 500= 2+2n -2
= 125 * 502 500=2n
= 62 750 n= 250
= (250/2) * (2+500) 500= 2+2n -2
= 125 * 502 500=2n
= 62 750 n= 250
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