Question

2,4,8,16.......finf the 10th term of G.P​

Answer 1

Answer:

The geometric sequence is given

2,4,8,16 ......

When provide with a geometric sequence we must first calculate the common ratio r .

r is obtained by dividing a term by its preceding term.

1)

$\frac{2}{4} = 2$

The 10th term can be obtained ratio r=2 the

first term = 2

Tn =arn-1

T10=2×2⁹

T10= 1024

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Answer 2

10th term of the GP = 1024

Correct question : 2 , 4 , 8 , 16 , . . . . Find the 10th term of G.P

Given :

The GP : 2 , 4 , 8 , 16 , . . . .

To find :

10th term of the GP

Concept :

For a geometric progression (GP)

$\displaystyle \sf{ }nth \: term \: of \: the \: GP = a \times {r}^{n - 1}$

Where , first term = a and common ratio = r

Solution :

Step 1 of 2 :

Find first term and common ratio

Here the given geometric progression (GP) is 2 , 4 , 8 , 16 , . . . .

First term = a = 2

Common ratio = r = 4/2 = 2

Step 2 of 2 :

Calculate 10th term of the GP

10th term of the GP

$\displaystyle \sf{ = a \times {r}^{10 - 1} }$

$\displaystyle \sf{ = a \times {r}^{9} }$

$\displaystyle \sf{ = 2 \times {2}^{9} }$

$\displaystyle \sf{ =2 \times 512 }$

$\displaystyle \sf{ = 1024 }$

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