Question

2.4 g metal displaces 0.56 L H2 , at NTP, then what
would be the equivalent weight of metal?
(1) 96
(2) 48
(3) 24
(4) 12​

Answer 1

Answer:

48

Explanation:

Answer 2

2.4 g metal displaces 0.56 L H2 , at NTP, then what

would be the equivalent weight of metal?

Correct answer is (3) 24.

Given

$W_{M} = 2.4 g$

$V_{H_{2} } = 0.56 L$

Find

weight of metal.

Solution

Now,

$E = \frac{11.2}{1.12}$ ×$W_{M}$

$E = \frac{11.2}{1.12}$×$2.4$

$E = 10$×$2.4$

$E = 24 g$

#SPJ3