2.4 g of Mg is treated with 200 mL of 1M H2SO4
and solution diluted to 1 L. Molar concentration
of H2SO4 in dilute solution is
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Answer:
Molar concentration of acid is 0.1
Explanation:
Number of moles of 2.4g Mg = 2.4/24= 0.1 M Mg
Now molarity of 200ml 1M H2So4 is 0.2M
Therefore when we react 0.1M of Mg with 0.2 of H2So4, then remaining amount of H2So4 will be 0.1 m, means 100ml of acid will be left behind.
Molar concentration of acid when it is diluted is;
Number of moles of acid = 100/1000 x 1 = 0.1 moles
Molar concentration will be 0.1
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