Question

2.4 into 10 to the power 20 electrons flow through a circuit in 10 hours calculate the magnitude of the current​

Answer 1

hey there

refer to attachment

Answer 2

The magnitude of the current​ through a circuit is $1.06\times 10^{-3}\ A$.

Explanation:

It is given that,

Number of electrons, $n=2.4\times 10^{20}$

Time, t = 10 hours = 36000 s

We know that current flowing through the circuit is given by the net charge per unit time. It is given by :

$I=\dfrac{q}{t}$

According to quantization of charge, q = ne

$I=\dfrac{ne}{t}$

$I=\dfrac{2.4\times 10^{20}\times 1.6\times 10^{-19}}{36000}$

$I=0.00106\ A$

or

$I=1.06\times 10^{-3}\ A$

So, the magnitude of the current​ through a circuit is $1.06\times 10^{-3}\ A$. Hence, this is the required solution.

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