Question

2
4
The equation of projectile is y = 16x-2
the horizontal range is​

Answer 1

Answer:

ANSWER

horizontal range is when the parabola cross the axis. it is going to cut x -axis at two points and the distance between them is the range.

y=16x−

4

x

2

0=16x−

4

x

2

x

1

=0 and x

2

=64 are two roots of above equation

therefore range is R=x

2

−x

1

=64−0=64m

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Please find the attachment and hope it helps u.