Question

—2 (4-x)= 6(x +2) +3x​

Answer 1

Answer:

-8+2x=6x+12+3x

6x+12+3x+8-2x

7x+20

x= -20/7

Answer 2

Given equation,

$-2 (4-x)= 6(x +2) +3x$

Here we have to find the value of $x$

$-2 (4-x)= 6(x +2) +3x$

$-8+2x=6x+12+3x$

$2x-8=9x+12$

First move all $x$ terms to LHS and all constant terms to RHS.

$9x-2x=-12-8$

$7x=-20$

Taking $7$ from LHS to RHS

We get,

$x=\frac{-20}{7}$

Therefore, the value of $x$ is $\frac{-20}{7}$