Question

2.42g ofcopper gave 3.025g of a black oxide of copper 6.49g of a black oxide on reduction with hydrogen gave 5.192g of copper. show that these figures are in accordance with law of constant proportion2.42g ofcopper gave 3.025g of a black oxide of copper 6.49g of a black oxide on reduction with hydrogen gave 5.192g of copper. show that these figures are in accordance with law of constant proportion2.42g ofcopper gave 3.025g of a black oxide of copper 6.49g of a black oxide on reduction with hydrogen gave 5.192g of copper. show that these figures are in accordance with law of constant proportion

Answer 1

2.42 gms of copper gives 3.025 gms of black oxide(CuO)

=> percentage of copper in cuo = 2.42/3.025  x 100 = 80%

=> percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Similarly ,

6.49 gms of black oxide gave 5.192 gm of copper

=> Percentage of copper in cuo = 5.192/6.49  x 100 = 80 %

percentage of oxygen in cuo = 100 - 80 = 20 %

Ratio of copper : oxygen = 80 : 20 = 4:1

Hence in both the reactions the ratio of copper : oxygen is same

Hence these figures are in accordance with law of constant proportion

Answer 2

Answer:

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