Chemistry, asked by shilpiathari, 2 months ago

2.44 gram of Benzoic acid
dissolved in benzine to form
Solution ? then find out
molarity
and formality ?
500ml​

Answers

Answered by thanvi13
0

Answer:

Correct option is

A

99.2 %

Given,

W

B

=2g,K

f

=4.9KKgmol

−1

W

A

=25g,ΔT

f

=1.62K

Now,

ΔT

f

=K

f

×

M

B

W

B

×

W

A

1000

M

B

=

1.62×25

4.9×2×1000

=241.98g/mol

2C

6

H

5

COOH⇌(C

6

H

5

COOH)

2

If x is the degree of association, (1−x) mole of benzoic acid left undissociated & corresponding x/2 as associated moles of C

6

H

5

COOH at equilibrium.

∴ Total number of moles of particles at eqm,

⇒1−x+

2

x

=1−

2

x

=i

⇒i=

Abnormalmolecularmass

Normalmolecularmass

⇒1−

2

x

=

241.98

122

2

x

=1−

241.98

122

⇒x=0.992=99.2%

∴ Degree of association of benzene =99.2%

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