Science, asked by shilpiathari, 3 months ago

2.44 gram of benzoic acid is dissolved in
benzine to form soo mi solution ! then
and formality a
find out molaring

Answers

Answered by arslanamjad876

1

Answer:

F=noof moles of solute /one unit of solvent

M Mass of Benzoic acid =122 as formula

C6H5COOH

Find mole =2.44/122=0.02

That is dimer multiple by 2

122×2=244. 0.25×2=0.5

F=0.02/244×0.5

Explanation:

F=noof moles of solute /one unit of solvent

M Mass of Benzoic acid =122 as formula

C6H5COOH

Find mole =2.44/122=0.02

That is dimer multiple by 2

122×2=244. 0.25×2=0.5

F=0.02/244×0.5

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