Question

2.44 gram of benzoic acid is dissolved in
benzine to form soo mi solution ! then
and formality a
find out molaring​

Answer 1

Answer:

F=noof moles of solute /one unit of solvent

M Mass of Benzoic acid =122 as formula

C6H5COOH

Find mole =2.44/122=0.02

That is dimer multiple by 2

122×2=244. 0.25×2=0.5

F=0.02/244×0.5

Explanation:

F=noof moles of solute /one unit of solvent

M Mass of Benzoic acid =122 as formula

C6H5COOH

Find mole =2.44/122=0.02

That is dimer multiple by 2

122×2=244. 0.25×2=0.5

F=0.02/244×0.5