2.46g of H2SO4 in 200ml of solution .find the molarity
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Molar mass of Sulphuric acid
= 2*H + 1*S + 4*O
= 2*1 + 32 + 4*16
= 2+32+64
= 98 u.
No of moles = Weight / Molar mass
= 46/98
= 23/49 moles.
Now.
Molarity = No of moles of solute / Mass of the solution
Molarity = 23/49 / 0.2 litres.
= 23 / 49 * 0.2
= 23/9.8 gmu/ l
= 2*H + 1*S + 4*O
= 2*1 + 32 + 4*16
= 2+32+64
= 98 u.
No of moles = Weight / Molar mass
= 46/98
= 23/49 moles.
Now.
Molarity = No of moles of solute / Mass of the solution
Molarity = 23/49 / 0.2 litres.
= 23 / 49 * 0.2
= 23/9.8 gmu/ l
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