Math, asked by milinayak, 10 months ago

2^4n+1 +2^9=2^10 find the value of n^n-1​

Answers

Answered by mhanifa
0

Answer:

2

Step-by-step explanation:

2^4n+1 + 2^9=2^10

n^n-1=?

================

  • 2^4n+1 + 2^9=2^10
  • 2*2^4n=2*2^9-2^9
  • 2*2^4n=2^9
  • 2^4n=2^8
  • 4n=8
  • n=2

n^n-1= 2^2-1=2^1=2

Answered by yogesh3singh
0

Answer:

2

Step-by-step explanation:

2^(4n+1) +2^9=2^10

=>2^4n+1 =2^10-2^9

=>2^4n+1=2^9

=>4n+1=9

=>n=2

Therefore n^(n-1)=2

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