2^4n+1 +2^9=2^10 find the value of n^n-1
Answers
Answered by
0
Answer:
2
Step-by-step explanation:
2^4n+1 + 2^9=2^10
n^n-1=?
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- 2^4n+1 + 2^9=2^10
- 2*2^4n=2*2^9-2^9
- 2*2^4n=2^9
- 2^4n=2^8
- 4n=8
- n=2
n^n-1= 2^2-1=2^1=2
Answered by
0
Answer:
2
Step-by-step explanation:
2^(4n+1) +2^9=2^10
=>2^4n+1 =2^10-2^9
=>2^4n+1=2^9
=>4n+1=9
=>n=2
Therefore n^(n-1)=2
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