2^4n+1 + 2^9=2^10 find the value of n^n-2
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Answered by
0
Answer:
1
Step-by-step explanation:
2^4n+1 +2^9=2^10
=> 2^4n+1=1024-512
=> 2^4n+1=512
=> 2^4n+1=2^9
=> 4n+1=9
=>4n=8
=> n=2
Therefore n^n-2= 2^2-2=2^0=1
Answered by
0
Answer:
1
Step-by-step explanation:
2^4n+1 + 2^9=2^10
n^n-2=?
================
- 2^4n+1 + 2^9=2^10
- 2*2^4n=2*2^9-2^9
- 2*2^4n=2^9
- 2^4n=2^8
- 4n=8
- n=2
n^n-2= 2^2-2=2^0=1
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