Math, asked by milinayak, 10 months ago

2^4n+1 + 2^9=2^10 find the value of n^n-2​

Answers

Answered by yogesh3singh
0

Answer:

1

Step-by-step explanation:

2^4n+1 +2^9=2^10

=> 2^4n+1=1024-512

=> 2^4n+1=512

=> 2^4n+1=2^9

=> 4n+1=9

=>4n=8

=> n=2

Therefore n^n-2= 2^2-2=2^0=1

Answered by mhanifa
0

Answer:

1

Step-by-step explanation:

2^4n+1 + 2^9=2^10

n^n-2​=?

================

  • 2^4n+1 + 2^9=2^10
  • 2*2^4n=2*2^9-2^9
  • 2*2^4n=2^9
  • 2^4n=2^8
  • 4n=8
  • n=2

n^n-2= 2^2-2=2^0=1

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