Question

2
4x^2 - 4ax + (a^2-b^2)=0
​

Answer 1

Step-by-step explanation:

4x^2-4ax+(a^2-b^2)=0

4ax+(a

2

−b

2

)=0

4x

2

−4ax+(a+b)(a−b)=0

⇒4x

2

+[−2a−2a+2b−2b]x+(a−b)(a+b)=0

⇒4x

2

+(2b−2a)x−(2a+2b)x+(a−b)(a+b)=0

⇒4x

2

+2(b−a)x−2(a+b)x+(a−b)(a+b)=0

⇒2x[2x−(a−b)]−(a+b)[2x−(a−b)]=0

⇒[2x−(a−b)][2x−(a+b)]=0

⇒2x−(a−b)=0,2x−(a+b)=0

⇒x=

2

a+b

,

2

a−b

.