Question

(2/5)-1/7+23/140-(1/7)3/4​

Answer 1

2/5*-1/7+23/140-1/7*3/4= 2/5*-1/7-1/7*3/4+23/140 (by the commutative law of addition )

=2/5×(-1/7)+(-1/7)×3/4+23/140

=-1/7(2/5+3/4)+23/140

=-1/7(8+15/20)+23/140. ( by the distributive law )

= -1/7(23/20)+23/140

= -23/140+ -23/140. ( by the additive inverse law )

= 0

Answer 2

Answer:

(2/5)-1/7+23/140-(1/7)3/4

2/5 -1/7+23/140-1/7x3/4

= -2/35+23/140-3/28

= -8/23-15/140

= 0 (Ans)