Question

2.5 ×10^-3J of work is done in a moving a charge of 0.6 columb from 1 point to another what is the potential difference between the two points?

Answer 1

Answer:

4.2 × 10^(-3) V

Explanation:

Potential Difference = Work/Charge

V = W/Q

W = 2.5 × 10^(-3) J

Q = 6 × 10^(-1) C

V = 2.5 × 10^(-3) J/6 × 10^(-1) C

=> V = 0.0042 V